jQuery isFunction() function is used to determines if its argument is callable as a function.
Syntax
jQuery.isFunction( value )
value - The value to be tested.
Example
Test a few parameter examples.
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>jQuery.isFunction demo</title>
<style>
div {
color: blue;
margin: 2px;
font-size: 14px;
}
span {
color: red;
}
</style>
<script src="https://code.jquery.com/jquery-3.4.1.js"></script>
</head>
<body>
<div>jQuery.isFunction( objs[ 0 ] ) = <span></span></div>
<div>jQuery.isFunction( objs[ 1 ] ) = <span></span></div>
<div>jQuery.isFunction( objs[ 2 ] ) = <span></span></div>
<div>jQuery.isFunction( objs[ 3 ] ) = <span></span></div>
<div>jQuery.isFunction( objs[ 4 ] ) = <span></span></div>
<script>
function stub() {}
var objs = [
function() {},
{
x: 15,
y: 20
},
null,
stub,
"function"
];
jQuery.each(objs, function(i) {
var isFunc = jQuery.isFunction(objs[i]);
$("span").eq(i).text(isFunc);
});
</script>
</body>
</html>
Output:
jQuery.isFunction( objs[ 0 ] ) = true
jQuery.isFunction( objs[ 1 ] ) = false
jQuery.isFunction( objs[ 2 ] ) = false
jQuery.isFunction( objs[ 3 ] ) = true
jQuery.isFunction( objs[ 4 ] ) = false
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