Write a C program to count the number of lines, words and characters in a given text

In this article, we will write a C program to count the number of lines, words, and characters in a given text.

ALGORITHM: 

Step 1: Start 

Step 2: Read the text until an empty line 

Step 3: Compare each character with newline char ‘\n’ to count the of lines 

Step 4: Compare each character with tab char ‘\t\’ or space char ‘ ‘ to count the of words 

Step 5: Compare the first character with NULL char ‘\0’ to find the end of a text 

Step 6: No of characters = length of each line of text 

Step 7: Print no of lines, no of words, no of chars 

Step 8: Stop. 

Write a C program to count the number of lines, words, and characters in a given text

#include <stdio.h>

void main()
{
	char line[81], ctr;
	int i, c,
	end = 0,
		characters = 0,
		words = 0,
		lines = 0;
	printf("TYPE ANY TEXT.\n");
	printf("GIVE ONE SPACE AFTER EACH WORD.\n");
	while (end == 0)
	{
		/*Reading a line of text */
		c = 0;
		while ((ctr = getchar()) != '\n')
			line[c++] = ctr;
		line[c] = '\0';
		/*counting the words in a line */
		if (line[0] == '\0')
			break;
		else
		{
			words++;
			for (i = 0; line[i] != '\0'; i++)
				if (line[i] == ' ' || line[i] == '\t')
					words++;
		}
		/*counting lines and characters */
		lines = lines + 1;
		characters = characters + strlen(line);
	}
	printf("\n");
	printf("Number of lines = %d\n", lines);
	printf("Number of words = %d\n", words);
	printf("Number of characters = %d\n", characters);
}

INPUT:

TYPE ANY TEXT.
GIVE ONE SPACE AFTER EACH WORD.
c programming source code examples

OUTPUT:

Number of lines = 1
Number of words = 5
Number of characters = 34

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