In this article, we will write a C program to count the number of lines, words, and characters in a given text.
ALGORITHM:
Step 1: Start
Step 2: Read the text until an empty line
Step 3: Compare each character with newline char ‘\n’ to count the of lines
Step 4: Compare each character with tab char ‘\t\’ or space char ‘ ‘ to count the of words
Step 5: Compare the first character with NULL char ‘\0’ to find the end of a text
Step 6: No of characters = length of each line of text
Step 7: Print no of lines, no of words, no of chars
Step 8: Stop.
Write a C program to count the number of lines, words, and characters in a given text
#include <stdio.h>
void main()
{
char line[81], ctr;
int i, c,
end = 0,
characters = 0,
words = 0,
lines = 0;
printf("TYPE ANY TEXT.\n");
printf("GIVE ONE SPACE AFTER EACH WORD.\n");
while (end == 0)
{
/*Reading a line of text */
c = 0;
while ((ctr = getchar()) != '\n')
line[c++] = ctr;
line[c] = '\0';
/*counting the words in a line */
if (line[0] == '\0')
break;
else
{
words++;
for (i = 0; line[i] != '\0'; i++)
if (line[i] == ' ' || line[i] == '\t')
words++;
}
/*counting lines and characters */
lines = lines + 1;
characters = characters + strlen(line);
}
printf("\n");
printf("Number of lines = %d\n", lines);
printf("Number of words = %d\n", words);
printf("Number of characters = %d\n", characters);
}
INPUT:
TYPE ANY TEXT.
GIVE ONE SPACE AFTER EACH WORD.
c programming source code examples
OUTPUT:
Number of lines = 1
Number of words = 5
Number of characters = 34
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