Write a C program to find the roots of a quadratic equation

In this article, we will write a C program to find the roots of a quadratic equation.

ALGORITHM: 

Step 1: Start 

Step 2: Read a,b,c 

Step 3: calculate disc = b*b-4*a*c 

Step 4: if(disc>0) Begin 

Step 5: root1=(-b+sqrt(disc))/(2*a) 

Step 6: root2=(-b-sqrt(disc))/(2*a) 

Step 7: Print “Root1” , “Root2” End 

Step 8: else if(disc=0) Begin 

Step 9: root1=-b/(2*a) 

Step 10: root2=root1; 

Step 11: Print “Root1” , “Root2” End 

Step 12: else 

Step 13: Print Roots are imaginary 

Step 14: Stop 

Write a C program to find the roots of a quadratic equation

#include <stdio.h>
#include <conio.h>
#include <math.h>

int main()
{
	int a, b, c;
	float disc, root1, root2;
	float img, real;
	printf("ENTER VALUES FOR a,b,c:\n");
	scanf("%d%d%d", &a, &b, &c);
	disc = (float) b *b - 4 *a * c;
	if (disc > 0)
	{
		printf("THE ROOTS ARE REAL &UNEQUAL:\n");
		root1 = (-b + sqrt(disc)) / (2 *a);
		root2 = (-b - sqrt(disc)) / (2 *a);
		printf("Root1=%f\n", root1);
		printf("Root2=%f\n", root2);
	}
	else if (disc == 0)
	{
		printf("THE ROOTS ARE REAL AND EQUAL:\n");
		root1 = -b / (2 *a);
		root2 = root1;
		printf("Root1=%f\n", root1);
		printf("Root2=%f\n", root2);
	}
	else
	{
		printf("THE ROOTS ARE IMAGINARY:\n");
		disc = -disc;
		img = (float) disc / 2 * a;
		real = (float) - b / 2 * a;
		if (img > 0)
		{
			printf("Root1=%f + i%f\n", real, img);
			printf("Root2=%f - i%f\n", real, img);
		}
		else
		{
			img = -img;
			printf("Root1=%f + i%f\n", real, img);
			printf("Root2=%f - i%f\n", real, img);
		}
	}
	return 0;
}

INPUT:

ENTER VALUES FOR a,b,c
1 4 4

OUTPUT:

THE ROOTS ARE EQUAL AND THEY ARE.. Root1=-2 Root2=-2 

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