In this Java program, we will use Scanner class to get the input from a user, and then we are using if-else statements to write the logic to check leap year.
Steps
Let's write a java program to check whether the input year is a leap year or not. Before we see the program, let's see how to determine whether a year is a leap year mathematically: To determine whether a year is a leap year, follow these steps:
- If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.
- If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.
- If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.
- The year is a leap year (it has 366 days).
- The year is not a leap year (it has 365 days).
Java Program to Check Leap Year
package com.javaguides.java.tutorial;
import java.util.Scanner;
/**
* Java Program to check Leap Year
*
* @author https://www.sourcecodeexamples.net/
*
*/
public class JavaProgram {
public static void main(String[] args) {
try (Scanner scanner = new Scanner(System.in)) {
System.out.println("Enter any Year:");
int year = scanner.nextInt();
boolean isLeap = false;
if (year % 4 == 0) {
if (year % 100 == 0) {
if (year % 400 == 0)
isLeap = true;
else
isLeap = false;
} else
isLeap = true;
} else {
isLeap = false;
}
if (isLeap == true) {
System.out.println(year + " is a Leap Year.");
} else {
System.out.println(year + " is not a Leap Year.");
}
}
}
}
Output:
Enter any Year:
2019
2019 is not a Leap Year.
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